Loading... ## 一元二次方程: $$ x = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a} $$ ```python import math def qiugen(a,b,c): dc = b/-2*a #对称轴 print ("对称轴"+str(dc)) try: #尝试求根,因为负数没法求根 x1 = -b+math.sqrt(b**2-4*a*c)/2*a x2 = -b-math.sqrt(b**2-4*a*c)/2*a if x1 == x2: return "只有一个解",x1 else: return "两个解",x1,x2 except: return "没有根" ``` [一元二次方程求根.html](http://blog.a152.top/usr/uploads/2021/08/3105466369.html) [一元二次方程求根.ipynb](http://blog.a152.top/usr/uploads/2021/08/272960599.ipynb) ## 二元一次方程 $$ \begin{cases} x+y=1\\ y-x=1\\ \end{cases} $$ ```python from sympy import * #导入 print("运算格式:+-*/等等") fc1l = input("输入方程1的左边") fc1r = input("输入方程1的左边") fc2l = input("输入方程2的左边") fc2r = input("输入方程2的右边") fc1l = "("+fc1l+")-("+fc1r+")" fc2l = "("+fc2l+")-("+fc2r+")" solve([fc1l,fc2l],[x, y]) ``` [解2元一次方程.ipynb](http://blog.a152.top/usr/uploads/2021/08/503337963.ipynb) [解二元一次方程.html](http://blog.a152.top/usr/uploads/2021/08/593130311.html) 咳咳,这里有一部分说明是乱写的,前面是用遍历实现的 Last modification:August 7, 2021 © Allow specification reprint Support Appreciate the author AliPayWeChat Like 1 如果觉得我的内容对你有用,请随意赞赏